Logics

[Tito]

I believe there was somewhere thread like this, this is some kind of quiz too ;P

Okey, an easy one for a begining, connect all the dots with 4 lines without breaking up the line ( Don't move the pen of the paper, or don't stop pushing the first button of the mouse in paint :) )

[efko.wbs]

at 2nd try (i saw it years ago but took short time to remember);
but nice one.

[CroNichaR]

at 2nd try (i saw it years ago but took short time to remember);
but nice one.

You have one more dot :D
Is mine OK??

[efko.wbs]

You have one more dot :D
Is mine OK??
L0l man! people always do one, and the same big mistake!:
,,they don't read the task properly,,(and thats why they fail many exams etc...)
Btw no your one is wrong (read Tito's post again and u will know why) :)

P.s. if u won't get it:
with 4 lines
P.S.. mine is O.K. for sure (cuz 4-lines; dots are connected)
__________________________________________________ __________________________


next one: change position of 2 matches to make 6 squares.

[Tito]

6 squares or 6 rectangles?

[klemen]

gg no re

http://shrani.si/f/1/Z8/3oMnI8N0/ggnore1.jpg

[oOGen.LaZOo]

1.

In any quadrilateral ABCD that is not a parallelogram , if O' lies on MN prove that:
Area(AO'B) + Area(CO'D) = Area(AO'D) + Area(BO'C)
2.

In a circumscribed quadrilateral ABCD if O is the center of the circle inscribed prove that:
Area(AOB) + Area(COD) = Area(AOD) + Area(BOC)
3.

From (1) and (2), O lies on MN.


What Line this is ?

[efko.wbs]

1. MN= AC or BD
2. any diameter of that circle

I am not sure at all.Tasks 1,2 belong together or they are separated?Lies MN in the same plain like ABCD?

[oOGen.LaZOo]

This is a proof of the XXXXX's Line . I will post you the drawing after you answer . And you'll see what the proof refers to .

[CaRaMBa]

This is a proof of the XXXXX's Line . I will post you the drawing after you answer . And you'll see what the proof refers to .

I think i proved it, but maybe its wrong. M and N are the midpoints of AC and BD diagonals but i've never heard about this line as a specific line.

BTW it's a very nice theorem if its right. (So the center of the inscribed circle of a circumscribed quadrilateral and the midpoints of the diagonals are colinear)

My problem: Show that there are infinite prime numbers (prime numbers are 2,3,5,7,11...) -i know 6 ways to prove it so you can use your creativity :)

[efko.wbs]

My problem: Show that there are infinite prime numbers (prime numbers are 2,3,5,7,11...) -i know 6 ways to prove it so you can use your creativity :)
1. they can be divided only by ,,1,, and its-self.
2.we write any amount of numbers for example 1-100 and then we take 2 and
scratch every multiple of it to 100,this we repeat with numbers 2-20.The
numbers that will stay non-scratched are prime numbers+ the prime numbers
from 1-20(can be prooved by method 1)

[CaRaMBa]

1. they can be divided only by ,,1,, and its-self.
2.we write any amount of numbers for example 1-100 and then we take 2 and
scratch every multiple of it to 100,this we repeat with numbers 2-20.The
numbers that will stay non-scratched are prime numbers+ the prime numbers
from 1-20(can be prooved by method 1)

I think you misunderstood the problem.
The problem is:
Proove that the prime numbers are uncountable, there are infinite of them. So you can't say that for example 35436346326513532343 is the largest prime number, there will be always a larger.

[oOGen.LaZOo]

So let's conclude

you proved me partially for 1. and 2.

If O' lies on MN we can finally conclude that they are collinear !! On that way it comes to the Newton's Line which refers to the line which in a circumscribed quadrilateral the center of the circle inscribed lies on the line joining the midpoints of the diagonals . So guys ... It's the Newton's line .

http://agutie.homestead.com/files/newtontheorem.gif

I learned how to prove it from mathlinks :)

[Tito]

Okey, connect the dots with 6 lines ( this is a bit more complicated of the first one, it took me like 10 min to solve it myself : ) )


Ah, I remembered one OOLDD puzzle too. You got two bottles of 3l and 5l, how will you gather 4l in the bottle of 5l? ( This is an easy one too, for rookies ;P ) ( you got as much water as you want to put in and out of the bottles : ) )

[Herr]

OOO hard one took me almost 3 seconds :D

88480

BTW my maximum score on dots was 15/16

1.

In any quadrilateral ABCD that is not a parallelogram , if O' lies on MN prove that:
Area(AO'B) + Area(CO'D) = Area(AO'D) + Area(BO'C)
2.

In a circumscribed quadrilateral ABCD if O is the center of the circle inscribed prove that:
Area(AOB) + Area(COD) = Area(AOD) + Area(BOC)

Lol pretty simple.. This same thing goes to both:
Area(AO'B) + Area(CO'D) = 1/2 Area(ABCD)
Area(AO'D) + Area(BO'C) = 1/2 Area(ABCD)

Area(AO'B) + Area(CO'D) = Area(AO'D) + Area(BO'C)

Once you trace the quadrilateral diagonals, pick opposite parts and you'll always have 1/2 of total area. I got the collinear thing but I don't see how it fits in your task, it is just additional analysis.

L0l man! people always do one, and the same big mistake!:
,,they don't read the task properly,,(and thats why they fail many exams etc...)
Btw no your one is wrong (read Tito's post again and u will know why) :)

P.s. if u won't get it:
with 4 lines
P.S.. mine is O.K. for sure (cuz 4-lines; dots are connected)
It seems like you didn't bother reading too, it says Don't move the pen of the paper and you did so :)

Tito, can we get those two solved?

[TP_MoonStar]

88487

Prove to me that i used more then 4 lines. (Y)

PS: I hate general maths.

[Tito]

efko.wbs got it right the first task with the 9 dots.

I will solve the task with the bottles, which is pretty easy as I said.. So, you full the bottle of 3l and add it into the 5l bottle, now you got 3l into the 3l bottle and 2l into the 5l bottle. You spit over the 3l bottle and you put the 2l of the 5l bottle there. You refull the 5l bottle and put 1l into the 3l bottle, what would make him totaly full and into the 5l bottle you will get left 4l :)


I will let you think a bit more of the task with 16 dots. HINT: Think a bit larger to the problem : )

[efko.wbs]

It seems like you didn't bother reading too, it says Don't move the pen of the paper and you did so :)
lol

______________________________________--
4 lines (this sux since this is possible)

[Tito]

That is with 6 lines..

[efko.wbs]

That is with 6 lines..
oki
this method is possible until the size of the dot is bigger than 1 pixel.

[Tito]

Use can't use the lines like that, they have to be STRAIGHT lines :) ( you can't select 2 rows of dots with 2 lines in any way ).

[CaRaMBa]

probably this one?

start from anywhere.

[Tito]

Only one line can pass in each dot, you can't use two lines on a dot.. Ye, its pretty unclearly given, but my english sux, that's a fact ;p

[efko.wbs]

do u know how it should be?
Imo there must be dot(s) crossed with more than 1 line.
Like your first task.There is dot with 3 lines, and it is right.

[Tito]

This is the first one.. There are no double lines on each dot.

[efko.wbs]

rly? Upper left dot has 2 lines.

[CaRaMBa]

I think Tito wants a solution like this:
You have to connect the 16 dots with 6 straight lines. During drawing you can't raise your pencil and you mustn't reach a dot more then 1 time (in Tito's solution for 9 dots he enters the upper left dot and leaves it, he went through it only 1 time.)

I'M still trying 16 dots :(

[CaRaMBa]

naaaaaaaaah
What about this one?

[Tito]

Yeah, I got that too..

Next " task ", an easy one too. You got two trains heading to each other on a 100km distance, like A -----100km----- B. One is driving with 20km/h and the other goes with 30km/h. If a beem started flying from the train A to the train B, and the opposite if gets to train B it starts going to train A and so on. ( the beam moves with 50km/h and starts with at the same time as the trains), how much will the beem pass till the trains meet?

[efko.wbs]

Yeah, I got that too..

Next " task ", an easy one too. You got two trains heading to each other on a 100km distance, like A -----100km----- B. One is driving with 20km/h and the other goes with 30km/h. If a beem started flying from the train A to the train B, and the opposite if gets to train B it starts going to train A and so on. ( the beam moves with 50km/h and starts with at the same time as the trains), how much will the beem pass till the trains meet?
100Km :)
20+30=50(in 1 hour they together pass 50km)........100km(total distance)/50=2(hours).
Beem(dunno wtf, probably should be bee)pass in 2 hours 100km.There is not important, that beem was flying between them, but how long time was flying.

[CaRaMBa]

I let others think about Tito's problem.
Here is a similar, a bit more difficult:
There are three snails standing at the angles of an equilateral trinalge (so every snail is at the same distance from the other two). The side of the triangle is L=50cm. "Snail A" is always going towards "Snail B", "Snail B" is always going towards "Snail C" and "Snail C" is always going towards "Snail A". Their velocity (movement speed) is the same, v=5cm/s.
a) Will they meet? (easy one)
b) If yes, where will they meet? (easy one)
c) If yes, when will they meet? (bit more difficult)
d) How many times do they go around the center of the triangle? (if you know a,b,c then its easy)


Hint: very basic physics is needed. You should know for example what relative velocity means.

[mestar.]

100Km :)
20+30=50(in 1 hour they together pass 50km)........100km(total distance)/50=2(hours).
Beem(dunno wtf, probably should be bee)pass in 2 hours 100km.There is not important, that beem was flying between them, but how long time was flying.

yep, but this problem is writen wrong here.
It should go like this:
Two trains are on the same track a distance 100 km apart heading towards one another, each at a speed of 50 km/h. A fly starting out at the front of one train, flies towards the other at a speed of 75 km/h. Upon reaching the other train, the fly turns around and continues towards the first train. How many kilometers does the fly travel before getting squashed in the collision of the two trains?

now its little bit more difficult xD

[oOGen.LaZOo]

88487

Prove to me that i used more then 4 lines. (Y)

PS: I hate general maths.

Well we can play with this for soo long and we still wont be able to come to a decision

4 lines : You can use four lines(one next to the other) with really big dimensions calculating that each of them has same length and each of them have same width and 4 x width = 1 x length . You get a square .

On this way you can get up to infinite ... I don't really want to start proving so let's say you used 8 lines and 8 x width = 1 x length ... (so solved using the dimensions of a single line)

Edit : Lol i didn't saw the symbol ... I proved that the painted square was filled by using 4 lines or more xD.

Well ( = one )=two Y = three so you used 5 lines . ( Y = \ + / + | ) :)

xD what am i doing . I will prove everything here xD

[CaRaMBa]

Edit : Lol i didn't saw the symbol ... I proved that the painted square was filled by using 4 lines or more xD.

Well ( = one )=two Y = three so you used 5 lines . ( Y = \ + / + | ) :)


OMG do you know what (Y) stands for? (for example msn) it's the icon of my post.
<-this instead of this-> xD

[efko.wbs]

yep, but this problem is writen wrong here.
It should go like this:
Two trains are on the same track a distance 100 km apart heading towards one another, each at a speed of 50 km/h. A fly starting out at the front of one train, flies towards the other at a speed of 75 km/h. Upon reaching the other train, the fly turns around and continues towards the first train. How many kilometers does the fly travel before getting squashed in the collision of the two trains?

now its little bit more difficult xD
75Km50+50=100(2trains pass for a 1 hour) so the fly will fly 1 hour...75Km.What is harder on it?U need just the time that take trains to crash.No matter how will the fly fly.


There are three snails standing at the angles of an equilateral trinalge (so every snail is at the same distance from the other two). The side of the triangle is L=50cm. "Snail A" is always going towards "Snail B", "Snail B" is always going towards "Snail C" and "Snail C" is always going towards "Snail A". Their velocity (movement speed) is the same, v=5cm/s.
a) Will they meet? (easy one)
b) If yes, where will they meet? (easy one)
c) If yes, when will they meet? (bit more difficult)
d) How many times do they go around the center of the triangle? (if you know a,b,c then its easy)

a)looks like, they can't meet cause after 10sec A will be in B, B will be in C, C will be in A (they will change theirs positions every 10sec, but they cant meet until they have the same speed
b)Nowhere
c)never
d)they will not meet
P.S. i am not sure

[CaRaMBa]

75Km50+50=100(2trains pass for a 1 hour) so the fly will fly 1 hour...75Km.What is harder on it?U need just the time that take trains to crash.No matter how will the fly fly.


a)looks like, they can't meet cause after 10sec A will be in B, B will be in C, C will be in A (they will change theirs positions every 10sec, but they cant meet until they have the same speed
b)Nowhere
c)never
d)they will not meet
P.S. i am not sure

Nono.
The snails always go towards each other. So if Snail B goes a bit up, snail A will change his movement direction too. So their movement direction always changes, because they always follow the other snail.
ok forget snails. let they be a destroyer, a water elemental and a gargoyle. You press attack with destroyer on elemental, press attack with elemental on gargoyle, and press attack with gargoyle on destroyer. The will go round and round and perhaps they meet somewhere. (Try it :))

[Tito]

Ye, indeed. since trains need 2 hours to meet, the beem will fly 2 hours too. 2x50=100km :)

EDIT: MMm, Caramba, L=50 or AB = 50cm? Because as far as I know, L=a+b+c, and on the pic you got only AB=L

[perito]

I let others think about Tito's problem.
Here is a similar, a bit more difficult:
There are three snails standing at the angles of an equilateral trinalge (so every snail is at the same distance from the other two). The side of the triangle is L=50cm. "Snail A" is always going towards "Snail B", "Snail B" is always going towards "Snail C" and "Snail C" is always going towards "Snail A". Their velocity (movement speed) is the same, v=5cm/s.
a) Will they meet? (easy one)
b) If yes, where will they meet? (easy one)
c) If yes, when will they meet? (bit more difficult)
d) How many times do they go around the center of the triangle? (if you know a,b,c then its easy)


Hint: very basic physics is needed. You should know for example what relative velocity means.

lol ofcourse they will meet, I made a java program that does this, this is a very famous problem called the Mice Problem (http://mathworld.wolfram.com/MiceProblem.html)

calculating the time is not very difficult also...

[efko.wbs]

Ahh i got it, but garg has melee attack, destro and ele has range(as element i used summoned pig by beastmaster) so it didn't worked.
They could meet at the middle of that triangle.They will move on some weird trajectory.But i think that they will make 1/3 of round arout that middle.
And i guess it will take 5 sec... I will look at it tommorow.

[CaRaMBa]

Ahh i got it, but garg has melee attack, destro and ele has range(as element i used summoned pig by beastmaster) so it didn't worked.
They could meet at the middle of that triangle.They will move on some weird trajectory.But i think that they will make 1/3 of round arout that middle.
And i guess it will take 5 sec... I will look at it tommorow.

yes they meet
yes at middle
time little bit more
think about that 1/3 round...perito's link could be useful, at least the simulations.

P.S.: but the correct value is there too :P

lol ofcourse they will meet, I made a java program that does this, this is a very famous problem called the Mice Problem (http://mathworld.wolfram.com/MiceProblem.html)

calculating the time is not very difficult also...

If its so easy for you then calculate the trajectory of snails in polar-coordinates :thumbUP:
believe me if you see this problem the first time, it's interesting and not so easy.

[Tito]

Okey, another easy one. Add numbers 1-9 into the sqares so the result will allways be 15 ( you can't repeat numbers, you should have every colone/row/mid diagonal to be 15 ( like a+b+c = 15 )

[efko.wbs]

Its needed to realize, that in middle or at corner can't be 1 or 9.
So in mid must be 5.Then from rest of numbers u need to make 3 pairs of numbers which together = 10 so: 3+7,4+6,2+8..............
And in the line with 9 must be numbers which together=6, and in the line with 1 numbers which together= 14, so only solution left (according to pairs):14=8+6;6=2+4;....

[Tito]

On a chess competition were played 210 matches, everyone played with the others only once. How many contestors were on the tournament?

[Ogi.]

i thought its easy, and draw that, but i noticed that 1 point goes through 2 times : ( and i can`t find otherr : ((
referring to 16 with 6 thingy ofc

[Dejan Roskovksi]

sudoku time :)) who will be the first to solve this .
I think you know the rules ofc.
1.In each horizontal and vertical line put the numbers from 1 to 9, and in each 3x3 sqares by the edges the numbers from 1 to 9

[perito]

-----------------------
| 1 7 8 | 9 6 5 | 3 4 2 |
| 6 9 3 | 8 4 2 | 5 1 7 |
| 5 4 2 | 3 7 1 | 8 6 9 |
-----------------------
| 7 1 6 | 5 3 9 | 2 8 4 |
| 2 5 4 | 7 8 6 | 9 3 1 |
| 3 8 9 | 2 1 4 | 7 5 6 |
-----------------------
| 4 3 7 | 6 2 8 | 1 9 5 |
| 9 2 1 | 4 5 3 | 6 7 8 |
| 8 6 5 | 1 9 7 | 4 2 3 |
-----------------------

[Dejan Roskovksi]

k, now an easy one:
1. Find the biggest plus on the picture
2. Some vilagers found an injured solder, and in which tomb did they barryed him?
Oh, and, in the empty boxes write anything.

[mestar.]

k, now an easy one:
1. Find the biggest plus on the picture
2. Some vilagers found an injured solder, and in which tomb did they barryed him?
Oh, and, in the empty boxes write anything.

1. the biggest plus is that one that is divideing that square in 4 parts.
2. injured soldier will go to hospital xD

btw. this sucks xD

[efko.wbs]

on A Chess Competition Were Played 210 Matches, Everyone Played With The Others Only Once. How Many Contestors Were On The Tournament?
21

[efko.wbs]

Hello,
this is task from IQ test i have just completed,
i think i got right answer.
Question is: which of those on bottom fit to empty space?

[sasha]

my guess goes to second picture.
three lines directed up.

[Artificial]

Same

mark every picture with numbers
if the lines are up, the numbers are positive
if the lines are down, the numbers are negative


In the first row, if you use addition to the first 2 pics you get the third pic
i.e 2 + 3 = 5
second row
2 +(-4) = -2
third row
4+(-1) = 3 => means 3 up

[efko.wbs]

Same

mark every picture with numbers
if the lines are up, the numbers are positive
if the lines are down, the numbers are negative


In the first row, if you use addition to the first 2 pics you get the third pic
i.e 2 + 3 = 5
second row
2 +(-4) = -2
third row
4+(-1) = 3 => means 3 up
thx, so i was right. :)

[kopec]

OK so i will add one old and easy one. Explain this:

[XFIRE]

It has the same explanation as this one ( for those who know ) :)

http://img139.imageshack.us/img139/5507/trougaosolvedke2bq0.gif

[efko.wbs]

OK so i will add one old and easy one. Explain this:
The slopes of the triangles are not exactly the same, but are the differences are so small that the human eye doesn't notice the difference. The difference is 1 square difference.Take a ruler.

[XFIRE]

Damn, I'll use Google next time too

[CaRaMBa]

Here is one for which you don't need difficult math's you only need to think

There is a 36-storey building and you have two eggs. They are identical. Assume that if you drop one from somewhere
a) it breaks and you can't use it anymore or
b) it will land safe and sound, it's properties doesn't change
Assume too that there is a storey (from number 1 to 36), from where if you drop the egg it breaks, and if you drop it from higher it will break surely and if you drop it from lower it won't break.

Your task: Measure the lowest hight from where if you drop the egg it breaks with minimum drops. (you can drop the egg from storey 1,2,3,4...36) You don't need to have egg at the end. Question: How much drops do you need to measure this in the worst case?
Be careful! You have only 2 eggs

[CaRaMBa]

Come on Guys, it's not so hard...
I tell you the solution for 1 egg and a 36 storey building.
You have to drop the egg from the storey's in this oreder: 1,2,3,4...36, because for example if you start from the second storey and it breaks, you can't decide whether the lowest hight is storey 1 or storey 2 because you have no eggs remaining. So in worst case you have to dropp eggs 36 times.

It's your turn to give the solution if you have two eggs.

[efko.wbs]

This is strange cause, normal egg breaks when it fall e.g. from 20 cm
so it should break after throwing from 1st storey.....
Assume that window of first storey is at least mby 40 cm above land.

[CaRaMBa]

This is strange cause, normal egg breaks when it fall e.g. from 20 cm
so it should break after throwing from 1st storey.....
Assume that window of first storey is at least mby 40 cm above land.

but assume that there is very-very-very soft sand under the window.

[fatman69]

hm.... first drop at 18m. if it doesn't break, test upper limits, if it does test lower. let's say it doesnt break, next step is 27,next is 31 or 22 etc...

so let's assume breaking point is 24.
1st test 18m->egg doesn't break
2nd test 27m->egg breaks
3rd test 22m->egg doesn't break
4th test-24m or 25m, free choice, if it breaks at 25m drop it at 24 as 5th test to conclude tests, if u drop at 24 and doesn't break, drop at 25 and so on...

so i'd say about 5 test drops is required,....

[Thunderman]

hmmm... i have one question,i think you will hardly answer it:
better from god
worse from evil
poor people dont have it
rich people dont need it
if you eat it,you may die

question is litlle retarted but its logical.

[Mr.7error]

Money ? Assuming the question is "little retarded"..

[CaRaMBa]

hm.... first drop at 18m. if it doesn't break, test upper limits, if it does test lower. let's say it doesnt break, next step is 27,next is 31 or 22 etc...

so let's assume breaking point is 24.
1st test 18m->egg doesn't break
2nd test 27m->egg breaks
3rd test 22m->egg doesn't break
4th test-24m or 25m, free choice, if it breaks at 25m drop it at 24 as 5th test to conclude tests, if u drop at 24 and doesn't break, drop at 25 and so on...

so i'd say about 5 test drops is required,....

more then 5
If you start from 18 and it breaks, you have to go on like 18, 1, 2, 3, ...17, in the worst case the breaking point is 17, and you need 18 drops in that case.

solution is between 5 and 18

ok, little help: start from the 8. storey and minimum required drops in worst case is 8. Why? And How do you go on if the breaks/doesn't break on 8th?

[KeweLi]

Which problem did you want me to solve? The egg one?

[VamoS_GringO]

Three men in a cafe order a meal the total cost of which is $15. They each contribute $5. The waiter takes the money to the chef who recognizes the three as friends and asks the waiter to return $5 to the men.

The waiter is not only poor at mathematics but dishonest and instead of going to the trouble of splitting the $5 between the three he simply gives them $1 each and pockets the remaining $2 for himself.

Now, each of the men effectively paid $4, the total paid is therefore $12. Add the $2 in the waiters pocket and this comes to $14.....where has the other $1 gone from the original $15?

[CaRaMBa]

Which problem did you want me to solve? The egg one?

exactly :)

Lil_GringO;822957']Three men in a cafe order a meal the total cost of which is $15. They each contribute $5. The waiter takes the money to the chef who recognizes the three as friends and asks the waiter to return $5 to the men.

The waiter is not only poor at mathematics but dishonest and instead of going to the trouble of splitting the $5 between the three he simply gives them $1 each and pockets the remaining $2 for himself.

Now, each of the men effectively paid $4, the total paid is therefore $12. Add the $2 in the waiters pocket and this comes to $14.....where has the other $1 gone from the original $15?

???
They paid 12: 10 to the chief, 2 to the waiter.
Original 15: 3 back to the customers, 2 at waiter 10 at chief
where is the problem?

[VamoS_GringO]

i found it on the net,didnt even read it since i was in a hurry to join a dota game :)
stupid riddle ^^

[Fika[F]]

I think you misunderstood the problem.
The problem is:
Proove that the prime numbers are uncountable, there are infinite of them. So you can't say that for example 35436346326513532343 is the largest prime number, there will be always a larger.

there is infinite amount of numbers so there is infinite prime numbers... simple as that...

[efko.wbs]

This riddle is easy: 1 brick weight 1kg+ 1half of brick, how much weight 2 bricks?

another: U go buy sweets and 1 pack of sweets contain 1 ticket, for 3 tickets u get another packet of sweets,and 1 pack of sweets cost 10 cents, how many packets of sweets can u get for 150 cents?
{on this failed my whole class except of me}

[obey.my.dreamz]

A : 2kg ?
b: haven't quite understood it well, but mb 21 ,? idk

[efko.wbs]

A : 2kg ?
b: haven't quite understood it well, but mb 21 ,? idk

A: no,.......... 1 brick = 1kg and half of brick.
B: No, whole class got 21 but its wrong :), imo u went on good way but....
So now little clearlier: U go to the shop with 150 cents,u want buy sweets,
1pack of sweets costs10 cents, 1pack of sweets contains 1 ticket,
For 3 tickets u get 1 new pack of sweets,So how many packs together you
can get for those 150 cents?

[obey.my.dreamz]

A : 4kg?
B : 22 ?

[mestar.]

zzz
A. its stupid, 3 kg but this is kinda riddle for kids and you wrote it wrong, it should be smth like this 1 and half fish cost 1.5 euro how much does 2 fish cost?
B. 20

[efko.wbs]

A : 4kg?
B : 22 ?
y :)

@mestar no its 4 / 22

[mestar.]

y :)

@mestar no its 4 / 22

lol i figured first one, its funny..x=1+1/2x
math gives answer quickly but dunno kinda stupid still...

second maybe explanation, i come out with 21 dunno where's the problem

[CaRaMBa]

y :)

@mestar no its 4 / 22

And how do you get the 22th sweet? You need the ticket inside it to buy it. I suppose you can't go in the shop and say:
"Hi, would you give me a sweet for 2 tickets? I have 2 tickets and I need the sweet first, and then i will pay the third"

Similar:
A friend of mine left his identification card somewhere. Someone sent him with the post. My friend had to go for it to the post. The attendant said:
Show me your identification card and i will give you your letter. My friend said that it's in the letter, he needs to open it first. But the attendant insisted on seing the identification card first, and give the letter after it, so my friend couldn't get his letter!!! emberrassing isn't it? Luckily her wife could get it with her own identification card :-)

Conclusion: You don't have enough money to buy the 22th sweet without using the 22th sweet, so my vote goes for 21.

[efko.wbs]

1. step u buy 15 packs of sweets right?
2 u will get 15 tickets=>5 new packets
3 from those 5 u will use 3 for 1 another pack, and 2 left
4 that 1 another pack contain 1 ticket+ those 2 that left=3 :)

So in the end u will have just 1 ticket from that last pack. :)

[mestar.]

yea got it also..dunno how i didnt first time :(

[mestar.]

you are standing on the top of the building and you have ampermeter, AC power source, Resistance of 100 ohm, and a lot of wire..
How do you measure building's height ?

[Sacred_Zd]

Simple.

R = ρ x l / S

I = U / R

so we have power source U, Resistance R = 100 ohm...wire with specific resistance ρ and surface S.
LoL mestar nuba, if we know Resistance is 100 ohm, than we don't need ampermeter hh
If R is unknown...using ampermeter we can calculate it R = U / I..

so l = R x S / ρ

I guess... :)

[obey.my.dreamz]

so , how tall is the building ?

[mestar.]

lol komi be silent, i kill you xD
The question is "How tall is the building?"
And i didnt say that whole building is resistance xD you nabcke xD

[CaRaMBa]

1. step u buy 15 packs of sweets right?
2 u will get 15 tickets=>5 new packets
3 from those 5 u will use 3 for 1 another pack, and 2 left
4 that 1 another pack contain 1 ticket+ those 2 that left=3 :)

So in the end u will have just 1 ticket from that last pack. :)

Yepp, i can't count, you are right :)

you are standing on the top of the building and you have ampermeter, AC power source, Resistance of 100 ohm, and a lot of wire..
How do you measure building's height ?


1. You go to the doorman of the building and say to him: "Hey friend, here is this nice new AC power source, i give it to you if you tell me how tall the building is."

2. You throw the apermeter from the top of the building and measure the time it falls with a clock. Then, you derive the differentialequation of the motion considering the resistance of the air too, and there you go, you have the height solving the equation.

3. You connect the wires with each other and with the resistance, and you slowly lower the resistance to the ground. Now you can measure the height easily with a ruler.

4. You make a pendulum out of a wire and the ampermeter. Measureing the frequency, you can estimate the change of the gravitic field, and you can calculate the height from it.

5. Well, now i can't imagine more silly solutions so:
You connect your wires, lower the middle of the long wire to the ground, connect the other two ends with the ampermeter and the resistance. You measure the resistance of the system (yeah, the wires have too), measure the resistance of a single wire, and there you go, calculate the length if the wires and the height of the building.

P.S.: do you know the story about Niels Bohr measureing the height of a building? :)

[mestar.]

xD so you find it on net..gj xD
actually the first time i heard it was from our Electrical circuits prof and the answer was really just throw ampermeter down, count the time and y=g/2 *t^2, then i found the improved story on probably the same site as you did..
btw no i didnt hear that story..

[CaRaMBa]

no i didn't, i just heard this story a long time ago :)

http://www.cooperativeindividualism.org/bohr_storyontests.html

It is said to be a real story

[Sacred_Zd]

so , how tall is the building ?

hh Calculation is not my profession xD

[obey.my.dreamz]

hh Calculation is not my profession xD

but i see that philosophy is ^^

[efko.wbs]

U have 8 balls, the same shape,colour,size.......
But 1 of them is heavier.U have only scales based on system as u can see on picture{idk its eng name}, How u can know which one is it, problem is u can weight them only 2x.

[obey.my.dreamz]

i can put only 2 balls on a scale at the same time ? rite? and i can measure only 2 times? those are the terms?

[mestar.]

hmm maybe this:
1. I put 3 of the on each side so 2 of them are left aside.
Now if the wage is in balance then its easy coz of the 2 left aside one is heavier and in next measure i will know..
If wage is not balance then I got rid of those 3 on the wage and 2 aside. So i only have to find it from those 3..So i again put 2 on the wage and one aside, and i can see just as earlier wich one is heavier.

[CaRaMBa]

U have 8 balls, the same shape,colour,size.......
But 1 of them is heavier.U have only scales based on system as u can see on picture{idk its eng name}, How u can know which one is it, problem is u can weight them only 2x.

Nice one :) solution hidden, let the others think
You put three of them to one side, three of them to the other

a) if they have equal mass, then one of the other 2 is the heavier, campare them and you will know which.
b) one side is heavier. Choose two of the heaviers and comapare them
1. if one of them is heavier, you have the heavier one
2. if equal, then the third is the heavier.
yeah, what mestar wrote...

[efko.wbs]

yes :) , i hoped it will take more time to solve :D

[obey.my.dreamz]

How many eggs can you put in an empty basket?

How can you add eight 8's to get the number 1,000? (only use addition)

[smaree]

How many eggs can you put in an empty basket?

As many as would fit into it

How can you add eight 8's to get the number 1,000? (only use addition)

888 + 88 + 8 + 8 + 8 = 1000


Am I right ? :)

EDIT: I can take anything you throw at me :)

[obey.my.dreamz]

yea, u ****en google freak ^^

btw 1st is wrong,. after u put 1st egg it's not empty anymore.

n1 : The following number is the only one of its kind. Can you figure out what is so special about it? 8,549,176,320.

[mestar.]

How many eggs can you put in an empty basket?

How can you add eight 8's to get the number 1,000? (only use addition)

w00t ?! XD

1. the answer is: Why should i put eggs in empty basket when i can make scramble eggs or ham and eggs xD
2. 1000/8=125 so i dont see where is the problem.

I think you only wrote half of question or smth coz its really stupid xD

edit: wow first one is nice but second still sucks coz you can just go like 8+8+8+8+8+8+8+8 till 1000 coz 1000 can be devided with 8.

edit2: lol me idiot xD I got lost in eights and 8 ... xD

[mestar.]

yea, u ****en google freak ^^

btw 1st is wrong,. after u put 1st egg it's not empty anymore.

n1 : The following number is the only one of its kind. Can you figure out what is so special about it? 8,549,176,320.

i already saw this one..:(
its about alphabet and first letter of those numbers

[obey.my.dreamz]

LOL Mestar u nuba, see "smare94" 's answer to eights question

[mestar.]

i know obey nabukodonozore xD
I just didn't realize what was the question coz its like use eight eights to found eight eights that are add to eights .. xD

[smaree]

The following number is the only one of its kind. Can you figure out what is so special about it? 8,549,176,320.

It's the only number that has all the digits arranged in alphabetical order.

8 - Eight
5 - Five

etc...

[CaRaMBa]

Next problem:
You have two "3" and two "8" digits. You can do any operations with them. Make 24.

For example: 38-(3*8)=12, but you need 24.

[smaree]

Next problem:
You have two "3" and two "8" digits. You can do any operations with them. Make 24.

For example: 38-(3*8)=12, but you need 24.

[(3+8) x 3] - 8 = 25
(8-3) x (8-3) = 25
[(8-3) x 3] + 8 = 23

I can't make it 24 ffs :S

Edit: I think this is a joke, It can't be made

[obey.my.dreamz]

i can
sqrt(8*8*3*3)

[smaree]

i can
sqrt(8*8*3*3)

Gj ;) :)

[Taz.]

Gj, btw, the sqrt means square root :p

[smaree]

1. Some months have 31 days; how many have 28?
2. Divide 30 by 1/2 and add 10. What is the answer?
3. If there are 3 apples and you take away 2, how many do you have ?
4. A doctor gives you three pills telling you to take one every half hour.
How many minutes would the pills last??
5. A farmer has 17 sheep, and all but 9 die. How many are left?

[obey.my.dreamz]

1.12
2.70?
3.2?
4.1h
5.9

too easy,... give sum harder,..

[smaree]

You found the 4th one on google 100% :)

[Taz.]

Here i got one: 1=0.999999999999999999999999999999 for ever.

True or not and why?

DONT USE GOOGLE!

[obey.my.dreamz]

@ smare, no i haven't! I don't do google in this thread.
@blazin true. "for ever " = infinity, and in infinity that function will reach 2 ..
aint sure bout this but i think it's correct...
If u watch train rails , for example,.. and u look at them far far away,.. and in one point ull see like they are bonding, making one ..

[Taz.]

Yep its true. 1=0.999999999 infinity..

http://www.blizzard.com/us/press/040401.html Link by smare94.

[smaree]

@ smare, no i haven't! I don't do google in this thread.
@blazin true. "for ever " = infinity, and in infinity that function will reach 2 ..
aint sure bout this but i think it's correct...
If u watch train rails , for example,.. and u look at them far far away,.. and in one point ull see like they are bonding, making one ..

Shtreberu xD >>> In english : Nerd

Just kidding :)

Come on dreamz... ask somethin' :D

[obey.my.dreamz]

^^

There are 2 ducks in front of 2 other ducks.
There are 2 ducks behind 2 other ducks.
There are 2 ducks beside 2 other ducks.


How many ducks are there?

[efko.wbs]

12?

[obey.my.dreamz]

lol nope ^^

[efko.wbs]

So 8?
Riddles of this kind are smth like games with words so sometimes solution is unexpectable :p

[obey.my.dreamz]

hehe ^^
sltn
x x
x x

[smaree]

there are 4... another one ? :)

[mestar.]

Ok this one is kinda famous and you can easily find it on google.
But try to solve it...
I did, so it shouldnt be real problem xD

Einstein wrote this riddle early In the 20th century. He said that 98% of the world's population could not solve it. There is no trick, just logic.

In a street, there are 5 houses, each in a different colour.

In each house lives a person with a different nationality.
These five owners drink a certain type of beverage, smoke a certain brand of cigar and keep a certain pet.
No owners have the same pet, smoke the same brand of cigar or drink the same beverage.

The question is: Who owns the rabbit?
Additional information:

The Brit lives in the red house
The Swede keeps dogs as pets.
The Dane drinks tea
The green house is on the left of the white house
The green house's owner drinks coffee
The person who smokes Pall Mall rears birds
The owner of the yellow house smokes Dunhill
The man living in the center house drinks milk
The Norwegian lives in the first house
The man who smokes Blends lives next to the one who keeps cats
The man who keeps horses lives next to the man who smokes Dunhill
The owner who smokes Bluemaster drinks beer
The German smokes Prince
The Norwegian lives next to the blue house
The man who smokes Blend has a neighbour who drinks water

[smaree]

germans house ?

[mestar.]

germans house ?


do you feel smarter after you type in google some problem and see solution made by some guy ? i think you are idiot xD

[RO]Claudiu : in my section of the forum there will be no insulting of other members , enjoy your 7 day ban .

[smaree]

No lol I just took pencil and paper and draw lol Its easy that way

[ce-ce muha]

hahha this kid smare is hilarious.
youa are 15 years old, i hardly belive that you took pencil and solve this test in 2 minutes xD
anyway any other tests ?

[obey.my.dreamz]

nah it aint easy,.. i dont have time to do it now, but remember we've done it in logic's class few years back,.. it's rly nice riddle... and i've solved it with a friend, took us a while...
but i heard there's few versions now,. dunno which is harder

btw why mestar banned ? and yeah, keep up with rids

[pRiMe]

Insulting...he said it in jest claudiu.

[obey.my.dreamz]

not?
edit: prime wtf are u doing in this subforum section LOL

[[RO]Claudiu]

hahha this kid smare is hilarious.
youa are 15 years old, i hardly belive that you took pencil and solve this test in 2 minutes xD
anyway any other tests ?

mestar i presume . do not underestimate anyone's inteligence if you dont know them and dont call them idiots .

Insulting...he said it in jest claudiu.

sorry bro , i just put myself in smare's position and i felt insulted . its not nice to call anyone idiot like that . and he acused smare of googling the answer , there is no way to know that , he may have googled it or he may have solved the ridle with his own whits . anyway next time ill just delete his insults if there will be any , lets hope not .

[obey.my.dreamz]

I think u're being 2 strict.

anyhow,.. back on topic

You are about to leave for holiday, but you forgot socks! You race back to your room, but all the lights are off, so you can't see the color of the socks.

Never mind, because you remember that in your drawer there are ten pairs of white socks, ten pairs of black socks, and eleven pairs of blue socks, but they are all mixed up.

How many of your socks do you need to take before you can be sure to have at last one matching pair?

[ce-ce muha]

CLAUDIU;861666']mestar i presume . do not underestimate anyone's inteligence if you dont know them and dont call them idiots .



sorry bro , i just put myself in smare's position and i felt insulted . its not nice to call anyone idiot like that . and he acused smare of googling the answer , there is no way to know that , he may have googled it or he may have solved the ridle with his own whits . anyway next time ill just delete his insults if there will be any , lets hope not .

is you lol ? its not underestimating its just fact, he is spoiling this thread..
He is googeling for answers its pathetic.
And btw calling him idiot was joke (there was xD after it) but you just had to ban som1 today...tt
hf all mighty mod xD (this was again joke)

[pecony_92]

: in my section of the forum there will be no insulting of other members , enjoy your 7 day ban .
this punishment is harsh and unnatural, this thing would be done with 5 infs or deleting post. punishment is radical, anyway he is spoiling the thread from what i saw ...
@mestar. well some ppl dont know our xD manners

[[RO]Claudiu]

lets take mesures , but not with insults nor with jokes containing insults . i do not insult other members and i expect you to do the same . if we cant be civilized then we are primitives .

come up with quizzes that google cant answer . the ultimate quiz . take them from books , not from the internet . google has the best crawler of all search sites so if there is anything on the internet related to the quiz google will find it . dam this google http://l.yimg.com/us.yimg.com/i/mesg/emoticons7/29.gif

:tiphat:

[pRiMe]

Anyway in this case i agree with claudiu,mestar is always joking but smare don't know him so he probably understood it as a insult.
@Jane oo am i not allowed to come here ?

[CaRaMBa]

Harder one:
8 3 8 3=24
put * / + or - to the spaces to correct the equation. You may use brackets anywhere.
So no sqrt now
btw gj mestar, i didn't thought of sqrt :)

@ obey:
4 if there is no difference between right and left legged socks. If there is, then it's 32 :hang:

[smaree]

I didn't google it it's easy... I don't care what are mestars manners and yes he said to me that Im an idiot... like ce-ce muha... belive what you want, I have 14 years, That doesn't change anything, So post questions and tasks and answer on the ones that others post, Don't come here to ley s.hit on me that I googled + When I solved it my brother knows this riddle and he said that Im right... what do you want more ??? Must I grow up to solve it ??? nah...

I think u're being 2 strict.

anyhow,.. back on topic

You are about to leave for holiday, but you forgot socks! You race back to your room, but all the lights are off, so you can't see the color of the socks.

Never mind, because you remember that in your drawer there are ten pairs of white socks, ten pairs of black socks, and eleven pairs of blue socks, but they are all mixed up.

How many of your socks do you need to take before you can be sure to have at last one matching pair?


Four ? Well it's 4 but I guess it's some trick, this way it's to easy

[[RiP]_HaCk3R]

nice smare nice :D

[smaree]

_HaCk3R;861830']nice smare nice :D

:) Who are you ? :)

[obey.my.dreamz]

easy one ;)

At a restaurant downtown, Mr. Red, Mr. Blue, and Mr. White meet for lunch. Under their coats
they are wearing either a red, blue, or white shirt.

Mr. Blue says, "Hey, did you notice we are all wearing different colored shirts from our names?" The man
wearing the white shirt says, "Wow, Mr. Blue, that's right!"

Can you tell who is wearing what color shirt?

[pRiMe]

Mr.red

[smaree]

easy one ;)

At a restaurant downtown, Mr. Red, Mr. Blue, and Mr. White meet for lunch. Under their coats
they are wearing either a red, blue, or white shirt.

Mr. Blue says, "Hey, did you notice we are all wearing different colored shirts from our names?" The man
wearing the white shirt says, "Wow, Mr. Blue, that's right!"

Can you tell who is wearing what color shirt?


Well Mr. Blue is not wearing white, and he can't wear blue cause it's his name so he wears red one

Mr White can't wear white caues its in his name, and he can't wear red because Mr blue does... so he is wearing blue one

and Mr red is wearing the white one :)

[obey.my.dreamz]

u must know this one

A farmer wants to cross a river and take with him a wolf, a goat, and a cabbage. There is a boat that can fit himself plus either the wolf, the goat, or the cabbage. If the wolf and the goat are alone on one shore, the wolf will eat the goat. If the goat and the cabbage are alone on the shore, the goat will eat the cabbage.

How can the farmer bring the wolf, the goat, and the cabbage across the river?

[smaree]

I will do yours.... you try solving this:

What is the easiest way to throw a ball, and have it stop, and completely reverse direction after traveling a short distance?

[obey.my.dreamz]

not to throw it at all? idk it's kind a not havin' enough of infs, mb spin it??

[smaree]

Since Posts can't be edited since the forum doesn't work quite well so I must duble-post

u must know this one

A farmer wants to cross a river and take with him a wolf, a goat, and a cabbage. There is a boat that can fit himself plus either the wolf, the goat, or the cabbage. If the wolf and the goat are alone on one shore, the wolf will eat the goat. If the goat and the cabbage are alone on the shore, the goat will eat the cabbage.

How can the farmer bring the wolf, the goat, and the cabbage across the river?

If he can go and return more times this is the solution:

He can go and take the goat across, then return and and take the wolf across and brings the goat back to the first side... then only the wolf will be on the other side, so now he can take cabbage accross and wolf won't eat it... and then he can take goat...

(my bro helped me a bit) :)

[smaree]

not to throw it at all? idk it's kind a not havin' enough of infs, mb spin it??

Throw it in the air right above you (straight) and it will stop on a moment and come back in the same dirrection

[[_FTG_]]

u must know this one

A farmer wants to cross a river and take with him a wolf, a goat, and a cabbage. There is a boat that can fit himself plus either the wolf, the goat, or the cabbage. If the wolf and the goat are alone on one shore, the wolf will eat the goat. If the goat and the cabbage are alone on the shore, the goat will eat the cabbage.

How can the farmer bring the wolf, the goat, and the cabbage across the river?

Lol this was question at our math competition in fourth grade of elementary school... Or at least was in practice book... U must find smth harder...
I have a book with nice ones but they are too long and I am too lazy to rewrite them :laugh:

[smaree]

Here are 2 easy ones...

1. What question can a person ask all they along and get different answer every time, and that answer is allways correct (Really easy)

2. what is the word that becomes shorter if you add two letters? (again easy)

[obey.my.dreamz]

2nd - mb short ?
wtf @ 1st ?? what time is it ?

[smaree]

y...

1st - What time is it?
2nd - short

You ask now :) ?

[obey.my.dreamz]

While walking across a bridge I saw a boat full of people. Yet on the boat there wasn't a single person. Why? am

[smaree]

While walking across a bridge I saw a boat full of people. Yet on the boat there wasn't a single person. Why? am

Well the boat was full of people, so if full of people, there is more then single person, right ?

[smaree]

or Every one on the boat is married. ???

Again sry for duble posting but posts can't be edited since the forum doesnt work properly... Whne It does, I will edit all this duble posts in one

[obey.my.dreamz]

or Every one on the boat is married. ???

Again sry for duble posting but posts can't be edited since the forum doesnt work properly... Whne It does, I will edit all this duble posts in one

*****! u read it somewhere , coz it should be " they were all couples" but i found on inet they also say "married" ccc

[smaree]

ok think what you want... I just guessed lol... and why it SHOULD be ? I can write it on the way I want... I don't care what you think...


You have a basket containing ten apples. You have ten friends, who each desire an apple. You give each of your friends one apple.

After a few minutes each of your friends has one apple each, yet there is an apple remaining in the basket.

How?

[[_FTG_]]

One of the friends got basket with apple in it...

[smaree]

Yea googler xD Kidding :D It's not hard

You ask ? :D

[[_FTG_]]

Lol googler... Gonna find some my books tomorrow.. Now i am too tired to write or read... To much of school lately XD

[efko.wbs]

:::::
U are in the room, there is nothing else than 3 switchs, each of them switch on/off 1 bulb in next room{3 switchs-3bulbs}.The task is: how to know that which switch control which bulb.Both rooms are dark, so its impossible to see from room with switchs to room with bulbs(visa-versa).And u can enter room with bulbs ONLY ONCE.

P.S. plz dont come with something like: i will write sms to my frien who is in the room with bulbs......
Use logic here and imagine that in practical life and u will get it.

[ce-ce muha]

smare, you really are ruining this thread. Its not fun at all to google every single problem, and plz dont say my brother or i figured it out coz its bull****..
Your average time of solving this problems is 3 minutes, you are pathetic, where is the fun if you are cheating, also you couldnt wait for 4 minutes before you answer your own question which you found on google ofc..
Dont you think its pathetic ? You are 14 years old go play with barbie its on your IQ level.. (again joke plz dont ban me me didnt mean harm)

[ce-ce muha]

:::::
U are in the room, there is nothing else than 3 switchs, each of them switch on/off 1 bulb in next room{3 switchs-3bulbs}.The task is: how to know that which switch control which bulb.Both rooms are dark, so its impossible to see from room with switchs to room with bulbs(visa-versa).And u can enter room with bulbs ONLY ONCE.

P.S. plz dont come with something like: i will write sms to my frien who is in the room with bulbs......
Use logic here and imagine that in practical life and u will get it.

so maybe its normal lights so they get warm ? warm-like 1min warmer-5min hot-10 ?

[efko.wbs]

so maybe its normal lights so they get warm ? warm-like 1min warmer-5min hot-10 ?

not so exact, but near :)

[obey.my.dreamz]

turn on one bulb wait for 10 mins after u check if its hot or not ^^

how about this1 :

You find yourself in a room, with nothing but a 2 doors and 2 guards guarding it... one door leads to the heaven and the other one to the total disaster. One of them guards always lie, the other one ,.. always tells truth. You get to ask only 1 guestion (AND ONLY 1 question to 1 guard not each ) what will u ask to be 100% sure to choose right door. You don't know which guard is a liar

[ce-ce muha]

not so exact, but near :)

xD my logic works.
but it can be shrinked a bit, so I one switch on and wait some time so it can get warm, than i turn it off and turn other switch on, imedietly i enter the room with bulbs (before first one gets cooler) and than i see that one bulb is turned on its the second switch, one bulb is warm its the first switch, and the last bulb is turned off..
yep this one is a bit faster, but i have all time in world so i use first solution xD

[ce-ce muha]

turn on one bulb wait for 10 mins after u check if its hot or not ^^

how about this1 :

You find yourself in a room, with nothing but a 2 doors and 2 guards guarding it... one door leads to the heaven and the other one to the total disaster. One of them guards always lie, the other one ,.. always tells truth. You get to ask only 1 guestion (AND ONLY 1 question to 1 guard not each ) what will u ask to be 100% sure to choose right door. You don't know which guard is a liar

This one is really old:
I will ask one of them what would this other guy say if i asked him what was right way ? And then i would choose opposite direction xD

[smaree]

smare, you really are ruining this thread. Its not fun at all to google every single problem, and plz dont say my brother or i figured it out coz its bull****..
Your average time of solving this problems is 3 minutes, you are pathetic, where is the fun if you are cheating, also you couldnt wait for 4 minutes before you answer your own question which you found on google ofc..
Dont you think its pathetic ? You are 14 years old go play with barbie its on your IQ level.. (again joke plz dont ban me me didnt mean harm)


Plz no ban ha ?? lol... I don't want to argue, I don't use google... My brother has 21 years and knows thousands of this riddles... so he can solve allmoust all of them... in the main IQ test he had max points...stfu plz and post if you want, If you don't want to... Leave this forum.

Claudiu : plz warn him cause I know he will continue

[CaRaMBa]

There is an isolated island in the middle of the Carabean. There live 5 very hungry and clever lions. One day, a helicopter drops a poisoned meat on the island. Who eats the meat, will fall asleep for a while, and he becomes vulnerable to attacks. His only luck is that his meat has become poisoned too, so if a lion eats him during sleeping, he will fall asleep for a while, and becomes vulnerable to attacks.

The question is:
Will the cleverest lion eat the meat or not?
(He doesn't want to risk his life, but he knows, that the others are clever too, and that they don"t want to die neither.)

Example: if there are 2 lions on the island, the cleverest won't eat the meat, coz the other would eat him during sleeping. Maybe he can eat if there are 5 or 6 lions?

I hope it's more clear now.

Harder one:
8 3 8 3=24
put * / + or - to the spaces to correct the equation. You may use brackets anywhere.
So no sqrt now


Its possible, not to easy and not on google...so gogo
****, yes its on google :(

[ce-ce muha]

you dont understand, its not if your brother can solve it or not..
You posted answer 2 mins after i wrote it..
And its just impossible that you even read it whole..
Most of these problems you just typed in google and copy paste the solution, its a fact, and its kinda hard for me to belive that your brother remembers word to word with punctional signs solutions on these problems..
So dont be a kid thats acting smart and admit it that you google every single of these questions..

LOL call mod to ban me xD really pathetic...
I have same message to claudio about you.
You will continue ruining this thread but whatever if it makes you happy..

[smaree]

I don't call an admin to ban you, I call him to warn/say to you that you stop insulting me cause I have 14 years... Ok message him what you want I dont care Cause I didnt do anything wrong... So plz stop and continue asking and answering...

[obey.my.dreamz]

i can get 24.3 with 8 8 3 3 . does that count? i mean,.. it's 24 w/o decimals ^^ or tranq(24.33)

btw i dont get ur lion story at all , it has too much directions,.questions and solutions,.. rearrange them sentences

[efko.wbs]

Solution to my case:
U switch on 1 switch, wait cca 5 minutes un the switch off it.
Turn on another switch, then enter room with bulbs.So the one which is lighting
is switch u turned on recently, the one of the 2 not lighting, which is warmer belongs to switch u turned on before.....

@Caramba ye it has many problems, etc .....
I think one solution could be: the smartest lion should hide e.g. in cave and wait while someone else will eat that meat.

[ce-ce muha]

Solution to my case:
U switch on 1 switch, wait cca 5 minutes un the switch off it.
Turn on another switch, then enter room with bulbs.So the one which is lighting
is switch u turned on recently, the one of the 2 not lighting, which is warmer belongs to switch u turned on before.....

hmmm didnt i already answer it ?

[efko.wbs]

whoops i didnt see it :D

[CaRaMBa]

@obey: it can be 24 exactly.
@efko: maybe i made it clearer now. For example if there is 1 lion he can eat the meat, but if there is 2 he can't. Can he if tehre is 5?

[smaree]

Two boys wish to cross a river. The only way to get to the other side is by boat, but that boat can only take one boy at a time. The boat cannot return on its own, there are no ropes or similar tricks, yet both boys manage to cross using the boat.

How ?

[[_FTG_]]

They are on different sides of river?
And for lion problem... Myb he will eat, cuz others wont dare to eat him knowing that there are more lions waiting for someone to eat poisoned meat... So if the smartest one eats it first he is safe XD
And the others will die of hunger XD

[smaree]

yea they are on the different sides... :)

[obey.my.dreamz]

omg i got the numbers part
(3/8)*3*8
^^
next plz, coz i rly dont get the lionz (=

[CaRaMBa]

I will try to find the problem in english and post then.
till then,
Four mathematicians have the following conversation:

Alice: I am insane.
Bob: I am pure.
Charlie: I am applied.
Dorothy: I am sane.
Alice: Charlie is pure.
Bob: Dorothy is insane.
Charlie: Bob is applied.
Dorothy: Charlie is sane.

You are also given that:

* Pure mathematicians tell the truth about their beliefs.
* Applied mathematicians lie about their beliefs.
* Sane mathematicians beliefs are correct.
* Insane mathematicians beliefs are incorrect.

Describe the four mathematicians.

from internet

[Taz.]

BTW guys here are sum signs u may need (copy paste them) :

² ³ ¼ ½ ¾ have fun.. :D

[efko.wbs]

This is for those who is over 7 years.
In the room are 4 corners.In every corner are 4 baskets.In every basket are 4 cats.Every cat has 4 baby-cats :) .How many legs are in the room?

[smaree]

4352 ?

[efko.wbs]

no :)

[[_FTG_]]

1280

[smaree]

;863514']1280

hahaha now that I recount It's 1280 ... I dont know how did I get 4000+ xD well if there are 20 cats in every basket 20 x 16 = 320

320 x 4 (legs) = 1280 ... lol :)

***************************************

You see a man looking at some small portrait in some street... then you ask him "who is that in the picture?" , and the man answers "Brothers and sisters, I have none, but that man's father, is my father's son."

Who's in the pic ? :)

[obey.my.dreamz]

damn that's a hell of a legs outhere

@ smare, it's obvious that it's the same man talking .

[smaree]

damn that's a hell of a legs outhere

@ smare, it's obvious that it's the same man talking .

No, read it again

[efko.wbs]

;863514']1280

yes :)

at smare: his son :)

[smaree]

at smare: his son :)

Aha, gj :)
******************
Two fathers took their sons fishing.

Each man and son caught one fish, but when they returned to camp there were only 3 fish. How could this be?

(None of the fish were eaten, lost, or thrown back.)

? :D

[[_FTG_]]

Grandfather, father and son went fishing next pls XD

[smaree]

;863606']Grandfather, father and son went fishing next pls XD

maths is fun ha xD cheater :D

[[_FTG_]]

Lol chetar as i said we were doing questions like this in 4-th grade of elementary...

[smaree]

lol no posts for a week.. .gotta change that xD

[KeweLi]

You are a computer... and the user inputs X (an integer).

Your job is to find the sum of the next 50 consecutive numbers of X. What is the fastest way? Note* You are not allowed to use formulas such as the "sum of the arithmetic series".

Stupid way:
(X+1) + (X+2) + (X+3) + (X+4) +...... (X+50)

The mathematical approach is 50(2x+49)/2, but it's not allowed.

[ce-ce muha]

....
sumx=0;
for(i=1;i<=50:i++)
sumx += i ;
....

i think..

[KeweLi]

Try to avoid using code language and explain it with English.

[obey.my.dreamz]

i don't get how u want us to do that if 50+ 49/2 isn't allowed,..
which form?

mb like this?

[ce-ce muha]

man that problem is stupid to explain in english..
all is written in that code..
sumX=0 // so first sumX is zero
for(i=1;i<=50;i++) //loop that goes from i=i to i=50 and every next time i will be i=i+1//
sumX+=x+i // so first time here it will be sumX= sumX+ (x+1); next time sumX=sumX + (x+2).......
so in the end when loop comes to 50th call in sumX will be all you wanted.

Since you asked if i was computer, this is how computer "thinks".

[obey.my.dreamz]

oh,.. he should say "in program language" ,.. like in pascaL:
(s: real;)
x:real;
begin

S:=0;
for i:= 1 to 50 do
begin
s:= s+x+i;
writeln(s);
end.
should b smth like that, i haven't done pascal for some time,..
it's also doable with "repeat" or "while" function

[smaree]

What is faster or train ? xD

[KeweLi]

Sorry I am not so sure what you guys typed.

1. X is the input number...

2. Set Counter = 0; Set Sum = X

3. Counter = Counter + 1

4. Does Counter = 50?

-If no: Sum = Sum + Counter + Sum
then go back to 3.

-If yes:

Something like that... my brain isnt functioning.

[ce-ce muha]

Sorry I am not so sure what you guys typed.

1. X is the input number...

2. Set Counter = 0; Set Sum = X

3. Counter = Counter + 1

4. Does Counter = 50?

-If no: Sum = Sum + Counter + Sum
then go back to 3.

-If yes:

Something like that... my brain isnt functioning.

man both mine and obeys solution does same thing probably.
Its just that we used the code.
more correct he used pascal and i used C.

[KeweLi]

You used C++ I think, and something else i dunno what lol.

Anyway, what I'm trying to say is that even my solution is not complete. Just hoping someone can help me finish it. xD

[ce-ce muha]

man we already solve your problem i dont see why do you need more help? "even my solution isnt complete" what do you mean by that ? Both obey and me solve it for you.
This is COMPLETE solution of your problem made in C.
I made it so it prints every step...
#include <stdio.h>
#include <stdlib.h>

int main() {
int sumX=0;
int i; int x;
scanf ("%d", &x);
for(i=1;i<=50;i++){
sumX+=x+i;
printf ("%d\n", sumX);
}
system("pause");
return 0;
}

so for input x=1, output will be:
1,2,5,9,14,......,1325


You said that we shouldnt use code, but its easier to make it this way and every other code has just minor changes coz they are all "thinking" the same way just sintaks is little different.

[KeweLi]

int main() {
int sumX=0;
int i; int x;
scanf ("%d", &x);
for(i=1;i<=50;i++){
sumX+=x+i;
printf ("%d\n", sumX);
}
system("pause");
return 0;
}


Yes, now it is complete. :)

[ce-ce muha]

You have 2 ropes. Each rope fully burns out after one hour. But they don't burn equally.(example half a rope can burn out in 10 minutes, and the other half only after the next 50 minutes).
Using only this two ropes you must measure exactly 45 minutes.

[ce-ce muha]

Try to get in every house all three things (electricity, water, gas) using pipes.
The pipes mustn't cross each other.

[KeweLi]

eee no idea for that house one...
Anyway I have another simple software one:

Desire: Software must total up the amount of money earned by a worker at the end of the week.

Jobs:
a) Bar Tender: $7 per hour
b) Programmer: $10 per hour
c) Grass Trimmer: $15 per hour

Notes:
- You cannot work for more than 20 hours each week.
- You are allowed to do different jobs for how ever long you want.
- There is a 10% tax of what they earn. Therefore, the software must display the pre-tax amount you earned, as well as the amount you will recieve.

[Taz.]

http://img293.imageshack.us/img293/2307/sanstitreiu1.png (http://img293.imageshack.us/my.php?image=sanstitreiu1.png)
http://img293.imageshack.us/img293/sanstitreiu1.png/1/w223.png (http://g.imageshack.us/img293/sanstitreiu1.png/1/)

How much triangles are there in that triangle?

[efko.wbs]

Try to get in every house all three things (electricity, water, gas) using pipes.
The pipes mustn't cross each other.

mby this?

[mestar.]

mby this?

nice try xD
actually answer is "It is impossible" xD

btw nobody figured out my first problem, one with ropes.



http://img293.imageshack.us/img293/2307/sanstitreiu1.png (http://img293.imageshack.us/my.php?image=sanstitreiu1.png)
http://img293.imageshack.us/img293/sanstitreiu1.png/1/w223.png (http://g.imageshack.us/img293/sanstitreiu1.png/1/)

How much triangles are there in that triangle?

there are many triangles xD

[mestar.]

guess this is it..
but i wouldn't call it logic, its simple math and basic knowledge of C.

#include <stdio.h>
#include <stdlib.h>
#include <math.h>

int main () {
int i;
float BarTender=0, Programmer=0, GrassTrimmer=0, sum;
for(i=0;i<=20; i++){
BarTender+= 7;
Programmer+=10;
GrassTrimmer+=15;
}
printf ("PreTax\n Bartender=%.2f, Programmer=%.2f, GrassTrimmer=%.2f",BarTender,Programmer, GrassTrimmer);
printf ("\nTax\n Bartender=%.2f, Programmer=%.2f, GrassTrimmer=%.2f", BarTender*0.1, Programmer*0.1, GrassTrimmer*0.1);
printf ("\n\nSum that I get if they all work for me= %.2f:", (BarTender+Programmer+GrassTrimmer)*0.1);
system("pause");
return 0;
}

[efko.wbs]

@ropes problem: we asume that for example 1 half of first rope burn same period as 1half of second rope etc.?


How much triangles are there in that triangle?

omg i doubt that u are from Canada as far as i know language spoken there is eng. and it almost pierced my eyes when i saw that :D
countable-many ; uncountable-much imo triangles can be counted.
on topic: i think 11

[mestar.]

You have 2 ropes. Each rope fully burns out after one hour. But they don't burn equally.(example half a rope can burn out in 10 minutes, and the other half only after the next 50 minutes).
Using only this two ropes you must measure exactly 45 minutes.

So those two ropes are identical but problem is that single rope doesn't burn in constant speed, example if you burn first rope it can burn half of it in 20 minutes and other half in 40 minutes. Same for second rope..
So you must find the way to measure exactly 45 minutes using only those two ropes and lighter.

[Taz.]

@ropes problem: we asume that for example 1 half of first rope burn same period as 1half of second rope etc.?



omg i doubt that u are from Canada as far as i know language spoken there is eng. and it almost pierced my eyes when i saw that :D
countable-many ; uncountable-much imo triangles can be counted.
on topic: i think 11


Wrong.

[T0mmy]

Thirteen unless I missed some =)

[Taz.]

Wrong.

[CaRaMBa]

15 triangles...but I'm not sure

You have 2 ropes. Each rope fully burns out after one hour. But they don't burn equally.(example half a rope can burn out in 10 minutes, and the other half only after the next 50 minutes).
Using only this two ropes you must measure exactly 45 minutes.

So those two ropes are identical but problem is that single rope doesn't burn in constant speed, example if you burn first rope it can burn half of it in 20 minutes and other half in 40 minutes. Same for second rope..
So you must find the way to measure exactly 45 minutes using only those two ropes and lighter.

nice one
put fire on both ends of one rope and at the same time put fire on ONE side of the other. When the first rope burns totally, 30 minutes will have elapsed. Now put fire on the other side of your other rope too. It will be 15min time from now to burn. 30+15=45

[Taz.]

14 triangles



nice one
put fire on both ends of one rope and at the same time put fire on ONE side of the other. When the first rope burns totally, 30 minutes will have elapsed. Now put fire on the other side of your other rope too. It will be 15min time from now to burn. 30+15=45


Nop, and please dont just guess all the numbers.

[mestar.]

nice one
put fire on both ends of one rope and at the same time put fire on ONE side of the other. When the first rope burns totally, 30 minutes will have elapsed. Now put fire on the other side of your other rope too. It will be 15min time from now to burn. 30+15=45

gj xD

btw I think 12 triangles..

[Taz.]

gj xD

btw I think 12 triangles..


Still wrong.....Soo? Give up?

[mestar.]

ok i tried again, maybe 16 last call..

[Taz.]

No no and no :). Want asnwer?

[mestar.]

well I really dont like this kind of "logic" xD sure enlighten us..

[Taz.]

17.

How ? Like this :

Count them by group.
Start with all the triangles done with 1.
Then all the triangles done with 2 pieces.
Then 3.
Then 4.
Etc..

Get the point?

[smaree]

17.

How ? Like this :

Count them by group.
Start with all the triangles done with 1.
Then all the triangles done with 2 pieces.
Then 3.
Then 4.
Etc..

Get the point?

Yes but I still can't get 17... nvm

[T0mmy]

Lol I was so far from the answer xD. Anyway, it's just counting anyway, you can miss some triangle.

[KeweLi]

guess this is it..
but i wouldn't call it logic, its simple math and basic knowledge of C.

You don't have to use C and it is simple logic.


printf ("PreTax\n Bartender=%.2f, Programmer=%.2f, GrassTrimmer=%.2f",BarTender,Programmer, GrassTrimmer);

printf ("\nTax\n Bartender=%.2f, Programmer=%.2f, GrassTrimmer=%.2f", BarTender*0.1, Programmer*0.1, GrassTrimmer*0.1);

printf ("\n\nSum that I get if they all work for me= %.2f:", (BarTender+Programmer+GrassTrimmer)*0.1);
}

Good but I think here, you made a mistake.
You need to add the total pre-tax amount (no tax) first,
then just times the total by 0.9 because the tax is 10% not 90%.

[CaRaMBa]

17.

How ? Like this :

Count them by group.
Start with all the triangles done with 1.
Then all the triangles done with 2 pieces.
Then 3.
Then 4.
Etc..

Get the point?

yepp i got the method and tried this way but still can't find 17
made of 1 piece: 4
made of 2 pieces: 6
made of 3 pieces: 3
made of 4 pieces: 3
great one: 1
ahh at last found them all

[smaree]

omg i doubt that u are from Canada as far as i know language spoken there is eng. and it almost pierced my eyes when i saw that :D
countable-many ; uncountable-much imo triangles can be counted.

He isn't from Canada, He lives there. Everybody makes mistake, you don't need to remark everyone.

[[RO]Claudiu]

He isn't from Canada, He lives there. Everybody makes mistake, you don't need to remark everyone.

indeed , lets stick to the topic please :)

[Taz.]

u got 4 triangles thats made with 1 piece.

then i tihnk 3 triangles done with 2 pieces ETc..........

[CaRaMBa]

U have 8 balls, the same shape,colour,size.......
But 1 of them is heavier.U have only scales based on system as u can see on picture{idk its eng name}, How u can know which one is it, problem is u can weight them only 2x.

Similar:

You have 13 balls, all the same shape,colour size....
But one of them has different mass, we don't know whether it's heavier or lighter.
U have only scales based on system as u can see on picture{idk its eng name}, How u can know which one is it? You can weight only 3 times.

http://www.eurobattle.net/attachment.php?attachmentid=101828&d=1223202483

[mestar.]

You don't have to use C and it is simple logic.



Good but I think here, you made a mistake.
You need to add the total pre-tax amount (no tax) first,
then just times the total by 0.9 because the tax is 10% not 90%.

ofc i dont have to use C, but you said that software must..
And yes its only math that i screwed up xD everywhere that i wrote 0.1* has to be 0.9. Kinda went fast through text...

[efko.wbs]

Similar:

You have 13 balls, all the same shape,colour size....
But one of them has different mass, we don't know whether it's heavier or lighter.
U have only scales based on system as u can see on picture{idk its eng name}, How u can know which one is it? You can weight only 3 times.

http://www.eurobattle.net/attachment.php?attachmentid=101828&d=1223202483
hmmm are u sure that there is exact solution?Cause i think its not possible.

[Mr.7error]

First of all, it can't be done imo if you don't know whether it's lighter or heavier. If you do:
Weigh 6 with 6, leaving one out. If it's balanced, then the one left out is the odd one. If not, you take the 6 you know are lighter/heavier and weigh 2 with 2. If balanced, weigh the other 2 one with the other and determin the solution. If not, same action, weigh the odd pair and find out the solution.

[CaRaMBa]

hmmm are u sure that there is exact solution?Cause i think its not possible.

yes, 100% sure

First of all, it can't be done imo if you don't know whether it's lighter or heavier.

If you would know that it's heavier or lighter, then you could separate it from 27 balls :)

[mestar.]

hmm when i start it comes to me that it should be 3 measure only but i cant get it with this 13. ball..
So for 12 balls its like this:

Take 1,2,3,4 and 5,6,7,8:

1. If equal--> ball is among (9,10,11,12)--> take 1,2,3 and 9,10,11:
/////////////////if "equal"--> 12 is our ball and next measure will determine if >or<
/////////////////if ">"--> take 9 and 10-->if "equal" 11 is our ball and its lighter
//////////////////////////////////////////-->if "not equal" lighter ball is up on wage.
/////////////////if "<"-->take 9 and 10--> if "equal" 11 is our ball and its heavier
//////////////////////////////////////////-->if "not equal" heavier ball is down.

2. If "not equal"--> we take 1,2,3,5 and 4,9,10,11--> if "equal" it means that we have to figure out from 6,7,8 ball which one is it..already solved...
////////////////////////////////////////////////////////--> if "<" or ">" only between two balls: 4 and 5

thats it for 12 balls i think..

[CaRaMBa]

hmm when i start it comes to me that it should be 3 measure only but i cant get it with this 13. ball..
So for 12 balls its like this:

Take 1,2,3,4 and 5,6,7,8:

1. If equal--> ball is among (9,10,11,12)--> take 1,2,3 and 9,10,11:
/////////////////if "equal"--> 12 is our ball and next measure will determine if >or<
/////////////////if ">"--> take 9 and 10-->if "equal" 11 is our ball and its lighter
//////////////////////////////////////////-->if "not equal" lighter ball is up on wage.
/////////////////if "<"-->take 9 and 10--> if "equal" 11 is our ball and its heavier
//////////////////////////////////////////-->if "not equal" heavier ball is down.

2. If "not equal"--> we take 1,2,3,5 and 4,9,10,11--> if "equal" it means that we have to figure out from 6,7,8 ball which one is it..already solved...
////////////////////////////////////////////////////////--> if "<" or ">" only between two balls: 4 and 5

thats it for 12 balls i think..

hmm...gj, you are very close to the solution

hint: i didn't say that you have to figure out whether the different ball is lighter/heavier. Just find it.

[mestar.]

old one:

You are on the quiz, you made it to final stage where you need to choose from 3 doors. Behind one door is car and behind other two is nothing.
So the host of the show asks you which door will you pick. You tell him that you choose door 1. Then he says "Good for you coz you didnt choose door number 3 coz behind them is nothing" and he opens that 3rd door and really there is nothing behind them. Now he asks you if you would maybe like to reconsider your first door pick choice.
Question: Will you decide to change your door 1 for door 2 or not? And why?

[CaRaMBa]

old one:

You are on the quiz, you made it to final stage where you need to choose from 3 doors. Behind one door is car and behind other two is nothing.
So the host of the show asks you which door will you pick. You tell him that you choose door 1. Then he says "Good for you coz you didnt choose door number 3 coz behind them is nothing" and he opens that 3rd door and really there is nothing behind them. Now he asks you if you would maybe like to reconsider your first door pick choice.
Question: Will you decide to change your door 1 for door 2 or not? And why?

21?
i don't wanna write solution since i know it :)

[2fuckingbitch]

I would stay on door 1 ....
My opinion > all !
No1 cant **** with me !

[efko.wbs]

@ mestar yes, because its kinda clear that behind nr.1 is nothing because:
in every show its basic thing to make show longer and
observers more nervous so it is like this 1-nothing, so if he
would reveal what is behind 2 it wouldnt be show cause there is car so he directly revealed nr.3(if there would be nothing behind nr2 he would reveal it after first choice, and ofc he cant reveal the door which he picked cause it wouldnt be show :D) is this right?

[obey.my.dreamz]

i think efko explained it better than it was in movie,.. it makes more sense to me.. but it's good one indeed

[mestar.]

nope actually its wrong.
You shouldnt think like that, I mean like this "host will try to trick me so i should stick to my door". What if host thinks that you think that he wants you to trick? Or what if host thinks that you think that he thinks that you think...you see what i mean ?

Actually the answer can be proved with math so try again.

In which case are better odds that you will win a car?

[efko.wbs]

hmmm so solution doesnt exist imo.Bcoz is its 50/50.

[mestar.]

nope its not 50/50 but ofc almost everybody says its 50/50

[obey.my.dreamz]

what's mestar is trying to say , is that by another choice, u get an extra 33.3% equaling 66,7% of guessing the right one,.. which is complete nonsense...it just sounded cool in movie,. but imho it has more phycological trick than logic(math)

[mestar.]

:D no obey ma man also think i am crazy xD
Actually it's not from the movie, it's well known problem also known as "Monty Hall problem".
http://en.wikipedia.org/wiki/Monty_Hall_problem

So the most logic way to explain this is:
In start you have 2/3 chances to pick wrong door, and only 1/3 chance to pick a car. So if we decide to switch our door later there will be more chance of winning a car.

[[RO]Claudiu]

nope its not 50/50 but ofc almost everybody says its 50/50

the moment he wants to convince you to change the door there is a higher probability that the car is behind it or not if he uses inverse psychology , he could be tricking you into thinking that he is tricking you that behind door #1 is the prize , so actualy it couldnt be .

this can only be told by the tone of his voice and the look in his eyes when he speaks , only then you can tell ...